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题解 | #岛屿数量#
DFS: once '1' is found then trigger dfs() to search all adjacent '1' and flip them as '0', since all adjacent '1' are regarded as one island. Use for ...
dfs
python
2021-08-05
0
493
题解 | #实现二叉树先序,中序和后序遍历#
Binary Tree Traversal: recursion class Solution: def threeOrders(self , root ): &...
recursion
Python
2021-08-05
0
378
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