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全部文章（共204篇）

CodeCraft-20 (Div. 2)B.String Modification

B. String Modification time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output Vasya has a string s o...

2020-05-01

0 633

CodeCraft-20 (Div. 2)C. Primitive Primes

C. Primitive Primes time limit per test1.5 seconds memory limit per test256 megabytes inputstandard input outputstandard output It is Professor R’s la...

2020-05-01

0 499

Codeforces Round #622 (Div. 2)C2. Skyscrapers (hard version) time limit per test3 seconds memory lim

C2. Skyscrapers (hard version) time limit per test3 seconds memory limit per test512 megabytes inputstandard input outputstandard output This is a har...

2020-05-01

0 681

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round)C. Remove Adjacent

C. Remove Adjacent time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output You are given a string s ...

2020-05-01

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Codeforces Round #626 (Div. 2, based on Moscow Open Olympiad in Informatics)C. Unusual Competitions

C. Unusual Competitions time limit per test1 second memory limit per test512 megabytes inputstandard input outputstandard output A bracketed sequence ...

2020-05-01

0 479

Educational Codeforces Round 83 (Rated for Div. 2) D. Count the Arrays

D. Count the Arrays time limit per test2 seconds memory limit per test512 megabytes inputstandard input outputstandard output Your task is to calculat...

2020-05-01

0 704

Codeforces Round #627 (Div. 3) D.Pair of Topics

D. Pair of Topics time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output The next lecture in a high...

2020-05-01

0 552

牛客练习赛59 石子搬运

https://ac.nowcoder.com/acm/contest/4743/E 就是说每次能取走一半我是这样想的如果先手取掉一半后的赢的是后手，那么先手就一定赢因为我取掉一半之后先手后手位置转变了先手取了这一部分剩下那部分的赢家是原来的后手此时先手变成了后手自然是最开始的先手...

2020-05-01

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Codeforces Round #628 (Div. 2)C. Ehab and Path-etic MEXs

C. Ehab and Path-etic MEXs time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output You are given a tr...

2020-05-01

0 551

＂中国东信杯＂广西大学第二届程序设计竞赛（同步赛)G.Antinomy与LaHee大森林

https://ac.nowcoder.com/acm/contest/2908/G 思路：显然地，对于n个点而言，总共可以走的路径数为n*(n-1) 对于所求地就有可走路径=总路径数-不可走路径数那么问题就转化成了如何计算不可走地路径数可以这样考虑对于节点a而言，他的子树的节点如果要走出这...

2020-05-01

0 810