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题解 | #二叉树中和为某一值的路径(二)#

/* struct TreeNode { int val; struct TreeNode *left; struct TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) { } };*/ class ...

2023-05-18

0 210

题解 | #从上往下打印二叉树#

/* struct TreeNode { int val; struct TreeNode *left; struct TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) { } };*/ #inclu...

2023-05-18

0 270

题解 | #树的子结构#

/* struct TreeNode { int val; struct TreeNode *left; struct TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) { } };*/ class ...

2023-05-18

0 198

题解 | #按之字形顺序打印二叉树#

/* struct TreeNode { int val; struct TreeNode *left; struct TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(N...

2023-05-18

0 215

题解 | #字符串的排列#

class Solution { public: vector<string> Permutation(string str) { vector<string> ans; if(str.size()==0){ r...

2023-05-18

0 261

题解 | #把二叉树打印成多行#

/* struct TreeNode { int val; struct TreeNode *left; struct TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(N...

2023-05-17

0 178

题解 | #两个链表的第一个公共结点#

/* struct ListNode { int val; struct ListNode *next; ListNode(int x) : val(x), next(NULL) { } };*/ class Solution { public: ListNode* FindF...

2023-05-17

0 195

题解 | #二叉搜索树的第k个节点#

/** * struct TreeNode { * int val; * struct TreeNode *left; * struct TreeNode *right; * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {...

2023-05-17

0 213

题解 | #二叉树中和为某一值的路径(一)#

/** * struct TreeNode { * int val; * struct TreeNode *left; * struct TreeNode *right; * }; */ class Solution { public: /** * * @...

2023-05-17

0 189

题解 | #求1+2+3+...+n#

class Solution { public: int Sum_Solution(int n) { n&&(n+=Sum_Solution(n-1)); return n; } };

2023-05-17

0 224