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题解 | #两个链表的第一个公共结点#

/* struct ListNode { int val; struct ListNode *next; ListNode(int x) : val(x), next(NULL) { } };*/ class Solution { public: ListNode* FindF...

2024-02-20

0 185

题解 | #删除链表的倒数第n个节点#

/** * struct ListNode { * int val; * struct ListNode *next; * ListNode(int x) : val(x), next(nullptr) {} * }; */ class Solution { public: /*...

2024-02-20

0 199

题解 | #链表中倒数最后k个结点#

/** * struct ListNode { * int val; * struct ListNode *next; * ListNode(int x) : val(x), next(nullptr) {} * }; */ class Solution { public: /*...

2024-02-20

0 200

题解 | #链表中环的入口结点#

/* struct ListNode { int val; struct ListNode *next; ListNode(int x) : val(x), next(NULL) { } }; */ class Solution { public:...

2024-02-20

0 142

题解 | #判断链表中是否有环#

/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} ...

2024-02-20

0 174

题解 | #合并两个排序的链表#

/** * struct ListNode { * int val; * struct ListNode *next; * ListNode(int x) : val(x), next(nullptr) {} * }; */ class Solution { public: /*...

2024-02-20

0 187

题解 | #反转链表#

/** * struct ListNode { * int val; * struct ListNode *next; * ListNode(int x) : val(x), next(nullptr) {} * }; */ class Solution { public: ...

2024-02-20

0 172

题解 | #链表内指定区间反转#

/** * struct ListNode { * int val; * struct ListNode *next; * ListNode(int x) : val(x), next(nullptr) {} * }; */ class Solution { public: /*...

2024-02-20

0 187