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题解 | #在二叉树中找到两个节点的最近公共祖先#

如果该节点不是O1也不是O2，那么O1与O2必然分别在该节点的左子树和右子树中如果该节点就是O1或者O2，那么另一个节点在它的左子树或右子树中稍微可以优化的一点就是，遇到O1或者O2节点就不往下递归了，把O1或者O2节点一层层往上传 /* * public class TreeNode {...

Java

2022-03-21

0 346

题解 | #二叉搜索树的最近公共祖先#

/* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * public TreeNode(int val) { * this.val...

Java

2022-03-21

0 334

题解 | #判断是不是平衡二叉树#

public boolean IsBalanced_Solution(TreeNode root) { return getDepth(root)!=-1; } private int getDepth(TreeNode root){ if(root=...

Java

2022-03-21

0 254

题解 | #判断是不是完全二叉树#

/* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * public TreeNode(int val) { * this.val...

Java

2022-03-21

0 332

题解 | #判断是不是二叉搜索树#

/* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * public TreeNode(int val) { * this.val...

Java

2022-03-21

0 314

题解 | #二叉树的镜像#

/* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * public TreeNode(int val) { * this.val...

Java

2022-03-20

0 218

题解 | #合并二叉树#

/* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * } */ public class Solution { /** ...

Java

2022-03-20

0 229

题解 | #对称的二叉树#

public class TreeNode { int val = 0; TreeNode left = null; TreeNode right = null; public TreeNode(int val) { this.val = val; ...

Java

2022-03-20

0 267

题解 | #二叉搜索树与双向链表#

public class TreeNode { int val = 0; TreeNode left = null; TreeNode right = null; public TreeNode(int val) { this.val = val; ...

Java

2022-03-20

0 236

题解 | #二叉树中和为某一值的路径(一)#

递归 /* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * } */ public class Solution { /** ...

Java

2022-03-16

0 261