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codeforces Round #610 E - The Cake Is a Lie
codeforces Round #610 E - The Cake Is a Lie 题目: https://codeforces.com/contest/1282/problem/E We are committed to the well being of all participant...
2020-11-21
0
444
Codeforces Round #612 (Div. 2) C. Garland
Codeforces Round #612 (Div. 2) C. Garland Vadim loves decorating the Christmas tree, so he got a beautiful garland as a present. It consists of n lig...
2020-11-21
0
518
codeforces Hello 2020 - E. New Year and Castle Construction
codeforces Hello 2020 - E. New Year and Castle Construction (待补) Kiwon’s favorite video game is now holding a new year event to motivate the users! ...
2020-11-21
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457
codeforces Hello 2020 D. New Year and Conference
codeforces Hello 2020 D. New Year and Conference (还没理解) 题意: Filled with optimism, Hyunuk will host a conference about how great this new year wil...
2020-11-21
0
485
Educational Codeforces Round 80 题解
Educational Codeforces Round 80 比赛链接: Educational Codeforces Round 80 A-Deadline 由 $ x + \frac{d}{x + 1} = (x + 1) + \frac{d}{(x + 1)} - 1$ , f (...
2020-11-21
0
484
Codeforces Round #615(Div.3)
Codeforces Round #615(Div.3) A. Collecting Coins 注意(n)可能不够用的情况。 #include<bits/stdc++.h> using namespace std; #define ll long long const int m...
2020-11-21
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398
Educational Codeforces Round 81 题解
Educational Codeforces Round 81 题解 A - Display The Number 肯定是1越多越好,因为位数越大越大,所以当n是2的倍数的时候,全是1 但是n可能不是n的倍数,此时应该有$( n - 3 ) / 2 $个 1 1 1和 1 1 1个 7 7 7...
2020-11-21
0
462
CF Round #620 E [1-Trees and Queries]
CF Round #620 E 1-Trees and Queries 题意:给你一颗树,进行 q q q次查询,每次查询时在树上加一条边,然后问此时两点间的距离能否为一个特定的值 k k k,(能反复经过同一个节点或同一条边)。 基本思路:加了一条边连接了x,y以后,a,b两点间的距离就...
2020-11-21
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506
Codeforces Round #622 C2 - Skyscrapers
Codeforces Round #622 C2 - Skyscrapers(单调栈) 题意: 给一个整数 n n n以及一个数组 m m m。 构建一个数组 a a a满足: 1 ≤ a i ≤ m i 1≤a_i≤m_i 1≤ai≤mi,且不存在这样的情况 j < i < k...
2020-11-21
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521
codeforces1312 D. Count the Arrays
codeforces1312 D. Count the Arrays 题目大意: 给定 n , m , n, m, n,m,在$1 ~ m $中取 n n n 个元素,有且只有两个元素相同,将它们排成在最大值左侧严格单增,在最大值右侧严格单减的序列。问这样的序列有多少个?答案对 9982443...
2020-11-21
0
472
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