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题解 | 考试分数(三)
select t2.id, t2.name, t2.score from (select t1.id, t1.name, t1.score, dense_rank() over(partition by ...
2025-06-26
0
10
题解 | 考试分数(二)
select t.id, t.job, t.score from (select id, job, score, case when score>avg(score) ove...
2025-06-26
0
8
题解 | 牛客每个人最近的登录日期(六)
select t1.name as u_n, t2.date as date, coalesce(t2.num, 0) as ps_num from user t1 inner join (select user_id, date, ...
2025-06-26
0
11
题解 | 牛客每个人最近的登录日期(五)
with newdetail as( select user_id, date, case when row_number() over(partition by user_id order by date asc)...
2025-06-25
0
16
题解 | 牛客每个人最近的登录日期(四)
select t1.date, sum(if_new) as new from (select l.user_id, l.date, case when row_number() over(partition by l...
2025-06-25
0
14
题解 | 牛客每个人最近的登录日期(三)
select round(count(distinct t2.user_id)/count(distinct t1.user_id),3) as p from (select user_id,date from login)t1 left join (select user_id,date from...
2025-06-24
0
20
题解 | 牛客每个人最近的登录日期(二)
with t1 as (select u.name as u_n, c.name as c_n, l.date, l.user_id from login l left join client c on l.client_id=c.id left join...
2025-06-23
0
20
题解 | 异常的邮件概率
with t3 as(select t1.email_id, t1.send_id,t1.ifsendblack, t2.receive_id,t2.ifreceiveblack, t2.type,t2.date from (select e.id as email_id, e.send_id,u....
2025-06-13
0
18
题解 | 刷题通过的题目排名
select *, dense_rank() over(order by number desc) as t_rank from passing_number
2025-06-06
0
18
题解 | 出现三次以上相同积分的情况
select t3.number from (select t1.number, count(*) as cnt from grade t1 join grade t2 where t1.number=t2.number and t1.id<...
2025-06-06
0
16
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