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题解 | #刷题通过的题目排名#

select id,number,dense_rank() over(order by number desc) as t_rank from passing_numberorder by t_rank,id排序函数：dense_rank(),按值排序，值相等时会重复，不会产生空位；

2021-08-12

0 289

题解 | #牛客的课程订单分析(一)#

select * from order_infowhere date>"2025-10-15"and status = 'completed'and product_name in('C++','Python','Java')order by id

2021-08-09

0 264

题解 | #获得积分最多的人(一)#

select user.name,t.grade_sum from(select user_id,sum(grade_num) as grade_sum from grade_info group by user_id order by grade_sum desc limit 1) tjoin u...

2021-08-06

0 238

题解 | #查找排除当前最大、最小salary之后的员工的平均工资avg_salary#

select avg(salary) as avg_salary from salarieswhere to_date = '9999-01-01' andsalary not in (select min(salary) from salaries where to_date = '9999-01...

2021-08-05

0 236

题解 | #使用子查询的方式找出属于Action分类的所有电影对应的title,description#

select f.title,f.description from film as f inner join film_category as fc on f.film_id = fc.film_idinner join category as c on c.category_id = fc.cat...

2021-07-30

0 320

题解 | #使用join查询方式找出没有分类的电影id以及名称#

select f.film_id,f.title fromfilm as f left join film_category as fc on f.film_id = fc.film_idleft join category as c on c.category_id = fc.category_i...

2021-07-30

0 314

题解 | #汇总各个部门当前员工的title类型的分配数目#

select d.dept_no,d.dept_name,t.title,count(*) fromdepartments as d inner join dept_emp as de on d.dept_no = de.dept_noinner join titles as t on t.emp_...

2021-07-29

0 313

题解 | #获取员工其当前的薪水比其manager当前薪水还高的相关信息#

SELECT emp_no,manager_no,emp_salary,manager_salaryFROM(SELECT de.emp_no,dept_no,salary AS emp_salaryFROM dept_emp AS de INNER JOIN salaries AS s1ON de...

2021-07-29

0 307

题解 | #获取所有非manager员工当前的薪水情况#

select de.dept_no,s.emp_no,s.salary from employees as einner join dept_emp as de on e.emp_no = de.emp_noinner join salaries as s on de.emp_no = s.emp_...

2021-07-29

0 260

题解 | #统计各个部门的工资记录数#

select de.dept_no,d.dept_name,count(s.emp_no) as sum from departments as d inner join dept_emp as de on d.dept_no = de .dept_noinner join salaries as ...

2021-07-28

0 235