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题解 | #句子逆序#

xin = [] if ' ' in x: for danci in x[::-1].split(' '): danci1= danci[::-1] xin.append(danci1) print(' '.join(xin)) else: p...

Python3

2022-04-19

0 314

题解 | #字符个数统计#

def count_character(str1): string = ''.join(set(str1)) count=0 for character in string: if 0<=ord(character)<=127: count += 1 e...

Python3

2022-04-18

0 237