题解 | #单链表的排序#

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 the head node
# @return ListNode类
#
class Solution:
    def sortInList(self , head: ListNode) -> ListNode:
        # write code here
        em = []
        this = head
        while this is not None:
            em.append(this.val)
            this = this.next
        em = sorted(em)
        newval = em[0]
        newhead = ListNode(newval)
        last = newhead
        for i in range(1,len(em)):
            thisnew = ListNode(em[i])
            last.next = thisnew
            last = thisnew
        
        return newhead