题解 | #分段函数#

#include <iostream>
#include <stack>
using namespace std;

float fun1(float x){
	return -x + 2.5;
}
float fun2(float x){
	return 2-1.5*(x-3)*(x-3);
}
float fun3(float x){
	return x/2 - 1.5;
}
 
int main(){
	int m,x;
	cin>>m;
	for(int i = 0; i < m; i++){
		cin>>x;
		if(x >= 0 && x < 2)
			printf("y=%.1f\n",fun1(x));
		else if(x >= 2 && x < 4)
			printf("y=%.1f\n",fun2(x));
		else if(x >= 4 && x < 6)
			printf("y=%.1f\n",fun3(x));
		
	}	

}