Implement strStr().
Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Example 1:
Input: haystack = "hello", needle = "ll" Output: 2
Example 2:
Input: haystack = "aaaaa", needle = "bba" Output: -1
Clarification:
What should we return when needle
is an empty string? This is a great question to ask during an interview.
For the purpose of this problem, we will return 0 when needle
is an empty string. This is consistent to C's strstr() and Java's indexOf().
这道题目显然是要考虑使用KMP算法的,那么现在就来写一个比较简单的KMP算法。
class Solution {
public:
int strStr(string haystack, string needle) {
int m = haystack.length(), n = needle.length();
if (!n) {//如果子字符串为空
return 0;
}
//kmp
for (int i = 0; i < m - n + 1; i++) {
int j = 0;
for (; j < n; j++) {
if (haystack[i + j] != needle[j]) {
break;
}
}
if (j == n) {
return i;
}
}
return -1;
}
};