题目:牛客网
解题思路:
看注释
public class Solution {
public void solveSudoku(char[][] board) {
//深度搜索
dfs(board, 0);
}
private boolean dfs(char[][] board, int step) {
// TODO Auto-generated method stub
int x, y;
if (step == 81) {
return isValidSudoku(board);
} else {
// 根据step确定行列x,y
x = step / 9;
y = step % 9;
if (board[x][y] != '.') {
// 如果x,y处不是'.'那么直接进一步深度搜索
if (dfs(board, step + 1))
// 当第81步,最后一处有数字,说明已经深度搜索完毕,直接return出来
return true;
} else {
// 需要填写数字,填写1-9判断是不是有效的数独输入
for (int i = 1; i < 10; i++) {
board[x][y] = (char) ('0' + i);
if (isValidSudoku(board))
if (dfs(board, step + 1))
return true;
//如果不是有效的数独,那么就回复现场继续尝试,当填了9也不行之后就
//return false回上一步
board[x][y] = '.';
}
}
return false;
}
}
public boolean isValidSudoku(char[][] board) {
// 行遍历和列遍历
for (int i = 0; i < 9; i++) {
int[] nums = new int[9];
for (int j = 0; j < 9; j++) {
if (board[i][j] >= '1' && board[i][j] <= '9') {
if (nums[(int) (board[i][j] - '1')] == 1) {
return false;
} else {
nums[(int) (board[i][j] - '1')] = 1;
}
}
}
int[] nums2 = new int[9];
for (int j = 0; j < 9; j++) {
if (board[j][i] >= '1' && board[j][i] <= '9') {
if (nums2[(int) (board[j][i] - '1')] != 0) {
return false;
} else {
nums2[(int) (board[j][i] - '1')] = 1;
}
}
}
}
// 遍历小九宮格
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
int[] nums = new int[9];
// 九宫格遍历
for (int k = 0; k < 3; k++) {
for (int k2 = 0; k2 < 3; k2++) {
if (board[i * 3 + k][j * 3 + k2] >= '1'
&& board[i * 3 + k][j * 3 + k2] <= '9') {
if (nums[(int) (board[i * 3 + k][j * 3 + k2] - '1')] != 0) {
return false;
} else {
nums[(int) (board[i * 3 + k][j * 3 + k2] - '1')] = 1;
}
}
}
}
}
}
return true;
}
}



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