排名存在并列情况,使用dense_rank()
select
log_day,
tb1.user_id,
hobby
from
(
select
date (log_time) as log_day,
user_id,
dense_rank() over (
partition by
date (log_time)
order by
time(log_time)
) as rk
from
login_tb
) as tb1
left join user_action_tb tb2 on tb1.user_id = tb2.user_id
where
rk = 1

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