题解 | 游游的整数切割

# # 超时
# n=str(input())
# pass_num=0
# for i in range(len(n)-1):
#     left = int(n[0:i+1])
#     right = int(n[i+1:])
#     if (left + right) % 2 == 0:
#         pass_num += 1
# print(pass_num)
n=input()
pass_num=0
x=int(n) % 2
if x == 0:
    # 切割后半截是偶数
    for i in range(len(n)-1):
        ele=int(n[i:i+1])   # 切割后前半截是偶数
        if ele in [0, 2, 4, 6, 8]:
            pass_num += 1
else:
    # 切割后半截是奇数
    for i in range(len(n)-1):
        ele=int(n[i:i+1])   # 切割后前半截是奇数
        if ele in [1, 3, 5, 7, 9]:
            pass_num += 1
print(pass_num)