#include <bits/stdc++.h>
using namespace std;
const int N=3e5+10;
const int mod = 998244353;
typedef long long ll;
typedef unsigned long long ull;
int n;
void solve()
{
cin>>n;
int sum=0;
int x = 2;
vector<int>ans;
for(int i=1;i<=n/2;i++)
{
ans.push_back(x);
sum+=x;
x+=2;
}
int y = 1;
for(int i=1;i<n/2;i++)
{
ans.push_back(y);
sum-=y;
y+=2;
}
int rest = sum;
if(rest%2==1)
{
cout<<"YES"<<'\n';
ans.push_back(rest);
for(auto x:ans)cout<<x<<' ';
cout<<'\n';
}
else cout<<"NO\n";
}
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t=1;
cin>>t;
while(t--)
{
solve();
}
return 0;
}
依旧是很好想的一个构造题

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