SELECT
    pay_ability,
    CONCAT(round(count(overdue_days) / count(1) * 100, 1),'%') as overdue_ratio
FROM
    loan_tb l
    LEFT JOIN customer_tb c ON l.customer_id = c.customer_id
GROUP BY
    pay_ability
order by 2 desc 
- 连接表获取贷款信息
- group by 获取没类信息,使用count得到占比
- 使用concat连接字符串

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京公网安备 11010502036488号