题解 | 日期累加

#include <cstdio>
#include <iostream>
#include <vector>
#include <string>
using namespace std;

vector<vector<int>> a = {
    {0,31,28,31,30,31,30,31,31,30,31,30,31},
    {0,31,29,31,30,31,30,31,31,30,31,30,31}
};


int main() {
    int n;
    cin>>n;
    for(int i=0;i<n;i++){
        int y,m,d,days;
        cin>>y>>m>>d>>days;
        days=days+d;
        d=0;
        vector<int>day = ((y%4==0&&y%100!=0)||y%400==0)?a[1]:a[0];
        while(days>(day[m])){
            if(m==12){
                y++;
                days-=(day[m]);
                m=1;
                d=0;
                day = ((y%4==0&&y%100!=0)||y%400==0)?a[1]:a[0];
                continue;

            }
            days-=(day[m]);
            m++;
            d=0;
        }
        d+=days;
        printf("%4d-%02d-%02d\n",y,m,d);
    }

    return 0;
}