题解 | 时间转换

#include <iostream>
using namespace std;

int main() {
    long long seconds;
    int hour,min,second;
    cin>>seconds;
    hour=seconds/3600;
    min=(seconds%3600)/60;
    second=seconds%60;
    cout<<hour<<" "<<min<<" "<<second<<endl;
}
// 64 位输出请用 printf("%lld")