- 2021年04月15日17:38:34愚蠢的代码
#include <iostream>
using namespace std;
int a[10010][10010] = {0};
int main() {
int row, col;
cin >> row >> col;
for (int i = 0; i < row; i++) {
for (int j = 0; j < col; j++) {
cin >> a[i][j];
}
}
for (int i = 0; i < row; i++) {
for (int j = 0; j < col; j++) {
int count = 0;
if (a[i][j] == '*') continue;
if (a[i - 1][j] == '*') count++;
else if (a[i + 1][j] == '*') count++;
else if (a[i][j - 1] == '*') count++;
else if (a[i][j + 1] == '*') count++;
else if (a[i + 1][j + 1] == '*') count++;
else if (a[i - 1][j + 1] == '*') count++;
else if (a[i + 1][j - 1] == '*') count++;
else if (a[i - 1][j - 1] == '*') count++;
a[i][j] = count;
count = 0;
}
}
for (int i = 0; i < row; i++) {
for (int j = 0; j < col; j++) {
cout << a[i][j] << endl;
}
}
return 0; - 2021年04月15日18:06:55
#include <iostream>
using namespace std;
int dx[] = {1, 1, 1, 0, 0, -1, -1, -1};
int dy[] = {-1, 0, 1, -1, 1, -1, 0, 1};
const int maxn = 105;
char g[maxn][maxn];
int n, m;
int main() {
cin >> n >> m;
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
cin >> g[i][j];
}
}
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
if (g[i][j] != '*') {
int count = 0;
for (int k = 0; k < 8; k++) {
if (g[i + dx[k]][j + dy[k]] == '*') count++;
}
cout << count;
} else {
cout << '*';
}
}
cout << endl; // 行末空格
}
return 0;
}