题解 | #a+b#

#include <stdio.h>
#include <string.h>
int main() {
    char a[1000] = {0};
    char b[1000] = {0};
    int A[1000] = {0};
    int B[1000] = {0};
    int C[1001] = {0};
    int jinwei = 0;
    int t = 0;
    while (scanf("%s %s", &a, &b) != EOF) {
        int len1 = strlen(a);
        int len2 = strlen(b);
        int len = len1 > len2 ? len1 : len2;
        for (int i = 0; i < len1; i++) {
            A[i] = a[len1 - 1 - i] - '0';
        }
        for (int j = 0; j < len2; j++) {
            B[j] = b[len2 - 1 - j] - '0';
        }
        for (int i = 0; i <= len; i++) {

            t = A[i] + B[i] + jinwei;
            C[i] = t % 10;
            jinwei = t / 10;
        }
        while (C[len] == 0) { //处理前导0
            if (len == 1) {
                break;
            }
            len--;
        }
        for (int i = len; i >= 0; i--) {
            printf("%d", C[i]);

        }
        printf("\n");
    }
}