这题只要留心输出的结果的范围即可
#include <iostream>
#include <cmath>
#define P 3.156*pow(10,7)
using namespace std;
int main()
{
int age=0;
cin>>age;
cout<<(long long)(age*P)<<endl;
return 0;
}

这题只要留心输出的结果的范围即可
#include <iostream>
#include <cmath>
#define P 3.156*pow(10,7)
using namespace std;
int main()
{
int age=0;
cin>>age;
cout<<(long long)(age*P)<<endl;
return 0;
}