HashMap源码put方法实现原理（jdk1.8）

源码解读

public V put(K key, V value) {
    //调用putVal()方法完成
    return putVal(hash(key), key, value, false, true);
}

final V putVal(int hash, K key, V value, boolean onlyIfAbsent,
               boolean evict) {
    Node<K,V>[] tab; Node<K,V> p; int n, i;
    //判断table是否初始化，否则初始化操作
    if ((tab = table) == null || (n = tab.length) == 0)
        n = (tab = resize()).length;
    //计算存储的索引位置，如果没有元素，直接赋值
    if ((p = tab[i = (n - 1) & hash]) == null)
        tab[i] = newNode(hash, key, value, null);
    else {
        Node<K,V> e; K k;
        //节点若已经存在，执行赋值操作
        if (p.hash == hash &&
            ((k = p.key) == key || (key != null && key.equals(k))))
            e = p;
        //判断链表是否是红黑树
        else if (p instanceof TreeNode)
            //红黑树对象操作
            e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value);
        else {
            //为链表，
            for (int binCount = 0; ; ++binCount) {
                if ((e = p.next) == null) {
                    p.next = newNode(hash, key, value, null);
                    //链表长度8，将链表转化为红黑树存储
                    if (binCount >= TREEIFY_THRESHOLD - 1) // -1 for 1st
                        treeifyBin(tab, hash);
                    break;
                }
                //key存在，直接覆盖
                if (e.hash == hash &&
                    ((k = e.key) == key || (key != null && key.equals(k))))
                    break;
                p = e;
            }
        }
        if (e != null) { // existing mapping for key
            V oldValue = e.value;
            if (!onlyIfAbsent || oldValue == null)
                e.value = value;
            afterNodeAccess(e);
            return oldValue;
        }
    }
    //记录修改次数
    ++modCount;
    //判断是否需要扩容
    if (++size > threshold)
        resize();
    //空操作
    afterNodeInsertion(evict);
    return null;
}