题解 | #创建动态数组#

#include <iostream>
using namespace std;

int main() {

    int n;
    cin >> n;
    
    // write your code here......
    int *p=new int[n];
    for(int i=n,j=0;i<=2*n-1,j<n;i++,j++){
        p[j]=i;
    }
    for(int i=0;i<n;i++){
        cout<<p[i]<<" ";
    }

    return 0;
}