题解 | 跳台阶

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param number int整型 
# @return int整型
#
class Solution:
    def jumpFloor(self , number: int) -> int:
        # write code here
        if number == 1:
            return 1
        dp = [0 for j in range(41)]
        dp[0] = 1
        dp[1] = 1
        for i in range(2, number+1):
            dp[i] = dp[i-1] + dp[i-2]
        return dp[number]