不会写，抄答案了qwq@烤点老白薯这题好难不会写

SELECT COUNT(distinct q2.device_id,q2.date)/count(DISTINCT q1.device_id,q1.date) as avg_ret
from question_practice_detail as q1 left outer join question_practice_detail as q2
on q1.device_id=q2.device_id and DATEDIFF(q2.date,q1.date)=1