题解 | #流程控制#

function fizzBuzz(num) {
if (num % 3 === 0 && num % 5 === 0){
return "fizzbuzz" 
}else if (num % 3 === 0){
  return "fizz"
}else if (num % 5 === 0){
  return "buzz"
						 } else if (num === undefined || typeof num !== 'number') {
						   return false
						 } else {
						   return num
						 }