本题要求实现给定二叉搜索树的5种常用操作。

函数接口定义：

BinTree Insert( BinTree BST, ElementType X );
BinTree Delete( BinTree BST, ElementType X );
Position Find( BinTree BST, ElementType X );
Position FindMin( BinTree BST );
Position FindMax( BinTree BST );

其中BinTree结构定义如下：

typedef struct TNode *Position;
typedef Position BinTree;
struct TNode{
    ElementType Data;
    BinTree Left;
    BinTree Right;
};
  • 函数Insert将X插入二叉搜索树BST并返回结果树的根结点指针；
  • 函数Delete将X从二叉搜索树BST中删除，并返回结果树的根结点指针；如果X不在树中，则打印一行Not Found并返回原树的根结点指针；
  • 函数Find在二叉搜索树BST中找到X，返回该结点的指针；如果找不到则返回空指针；
  • 函数FindMin返回二叉搜索树BST中最小元结点的指针；
  • 函数FindMax返回二叉搜索树BST中最大元结点的指针。

裁判测试程序样例：

#include <stdio.h>
#include <stdlib.h>

typedef int ElementType;
typedef struct TNode *Position;
typedef Position BinTree;
struct TNode{
    ElementType Data;
    BinTree Left;
    BinTree Right;
};

void PreorderTraversal( BinTree BT ); /* 先序遍历，由裁判实现，细节不表 */
void InorderTraversal( BinTree BT );  /* 中序遍历，由裁判实现，细节不表 */

BinTree Insert( BinTree BST, ElementType X );
BinTree Delete( BinTree BST, ElementType X );
Position Find( BinTree BST, ElementType X );
Position FindMin( BinTree BST );
Position FindMax( BinTree BST );

int main()
{
    BinTree BST, MinP, MaxP, Tmp;
    ElementType X;
    int N, i;

    BST = NULL;
    scanf("%d", &N);
    for ( i=0; i<N; i++ ) {
        scanf("%d", &X);
        BST = Insert(BST, X);
    }
    printf("Preorder:"); PreorderTraversal(BST); printf("\n");
    MinP = FindMin(BST);
    MaxP = FindMax(BST);
    scanf("%d", &N);
    for( i=0; i<N; i++ ) {
        scanf("%d", &X);
        Tmp = Find(BST, X);
        if (Tmp == NULL) printf("%d is not found\n", X);
        else {
            printf("%d is found\n", Tmp->Data);
            if (Tmp==MinP) printf("%d is the smallest key\n", Tmp->Data);
            if (Tmp==MaxP) printf("%d is the largest key\n", Tmp->Data);
        }
    }
    scanf("%d", &N);
    for( i=0; i<N; i++ ) {
        scanf("%d", &X);
        BST = Delete(BST, X);
    }
    printf("Inorder:"); InorderTraversal(BST); printf("\n");

    return 0;
}
/* 你的代码将被嵌在这里 */

输入样例：

10
5 8 6 2 4 1 0 10 9 7
5
6 3 10 0 5
5
5 7 0 10 3

输出样例：

Preorder: 5 2 1 0 4 8 6 7 10 9
6 is found
3 is not found
10 is found
10 is the largest key
0 is found
0 is the smallest key
5 is found
Not Found
Inorder: 1 2 4 6 8 9

BinTree Insert( BinTree BST, ElementType X )
{
	if(!BST){
		BST = (BinTree)malloc(sizeof(struct TNode));
		BST->Data = X;
		BST->Right=NULL;
		BST->Left=NULL;	
	} else if(X<BST->Data){
		BST->Left = Insert(BST->Left,X);
	} else if(X>BST->Data){
		BST->Right = Insert(BST->Right,X);
	}	
	return BST;
}
Position Find( BinTree BST, ElementType X )
{
	if(!BST) return NULL;
	if(X < BST->Data ){
		return Find(BST->Left,X);
	} else if(X>BST->Data) {
		return Find(BST->Right,X);
	} else 
		return BST;
	
}
Position FindMin( BinTree BST )
{
	if(BST){
		while(BST->Left!=NULL){
			BST = BST->Left; 
		}
	}
	return BST;
}
Position FindMax( BinTree BST )
{
	if(BST){
		while(BST->Right!=NULL){
			BST = BST->Right;
		}
	}
	return BST;
}
BinTree Delete( BinTree BST, ElementType X )
{	
	if(!BST){
		printf("Not Found\n");
		return BST;
	}
	if( X< BST->Data ){
		BST->Left = Delete(BST->Left,X);
	} else if(X>BST->Data){
		BST->Right = Delete(BST->Right,X);
	}else{
		BinTree p;
		if(BST->Left && BST->Right){
			p = FindMax(BST->Left);
			BST->Data = p->Data;
			BST->Left = Delete(BST->Left,BST->Data);
		}else {
			p = BST;
			if( !BST->Left ){
				BST = BST->Right; 
			} else if(!BST->Right) {
				BST = BST->Left;
			}
			free(p);
		}
	}
	return BST;
}