题解 | 合法IP

丑题多作怪！！！

1. 不要觉得我代码写的差~
2. 因为这是一个奇丑无比的题目~
3. 君子绕行~

import java.util.Scanner;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        String[] ipSubStr = in.nextLine().split("\\.");
        if (ipSubStr.length != 4) {
            System.out.println("NO");
            return;
        }
        int[] ipSubInt = new int[ipSubStr.length];
        boolean valid = true;
        for (int i = 0; i < ipSubStr.length; i++) {
            String ipSubs = ipSubStr[i];
            if (ipSubs.isEmpty()) {
                valid = false;
                continue;
            }
            if (ipSubs.length() > 1 && (ipSubs.charAt(0) < '1' || ipSubs.charAt(0) > '9')) {
                valid = false;
                continue;
            }
        try {
            ipSubInt[i] = Integer.parseInt(ipSubs);
            } catch (Exception e) {
                valid = false;
                break;
            }
            if (ipSubInt[i] > 255) {
            valid = false;
            break;
        }
    }
    System.out.println(valid ? "YES" : "NO");
    }
}