题解 | #Hello World for U#

#include <iostream>
#include <string>
#include <cstring>
using namespace std;
const int N = 30;
char res[N][N];
void printU(string s)
{
    memset(res, 0, sizeof res);
    int n = s.size();
    int n1 = (n + 2) / 3, n2 = n + 2 - 2 * n1;
    // cout << n1 << n2 <<endl;
    int i = 0, j;
    for(j = 1; j <= n1; j ++) res[j][1] = s[i ++];
    for(j = 2; j <= n2; j ++) res[n1][j] = s[i ++];
    for(j = n1 - 1; j; j --) res[j][n2] = s[i ++];
    for(int i = 1; i <= n1; i ++)
    {
        for(int j = 1; j <= n2; j ++)
        {
            if(res[i][j] != 0) cout << res[i][j];
            else cout << ' ';
        }
        cout << endl;
    }
}
int main() {
    string s;
    while (cin >> s) { // 注意 while 处理多个 case
        printU(s);
    }
}
// 64 位输出请用 printf("%lld")