题解 | 最大最小值

const rl=require('readline').createInterface({input:process.stdin})
const iter=rl[Symbol.asyncIterator]()
const readline=async ()=>(await iter.next()).value

void async function(){
    const lines=(await readline()).split(' ')
    const a = parseInt(lines[0])
    const b = parseInt(lines[1])
    const c = parseInt(lines[2])

    if (a >= 1 && b >= 1 && c >= 1 && a <= 1e6 && b <= 1e6 && c <= 1e6) {
        let max=a
        let min=b
        if (a>=b) {
            if(a>=c){
                max=a
                if(b>=c){
                    min=c
                    console.log('The maximum number is : ' +max+'\n'+
                        'The minimum number is : '+min)
                }else{
                    min=b
                    console.log('The maximum number is : ' +max+'\n'+
                        'The minimum number is : '+min)
                }
            }else {
                max=c
                min=b
                console.log('The maximum number is : ' +max+'\n'+
                    'The minimum number is : '+min)
            }

        } else if(a<=b){
            if(b>=c){
                max=b
                if(a>c){
                    min=c
                    console.log('The maximum number is : ' +max+'\n'+
                        'The minimum number is : '+min)
                }else{
                    min=a
                    console.log('The maximum number is : ' +max+'\n'+
                        'The minimum number is : '+min)
                }

            }else{
                max=c
                min=a
                console.log('The maximum number is : ' +max+'\n'+
                    'The minimum number is : '+min)
            }

        }

    } else {
        console.log('输入数据非法')
    }

    rl.close()
}()