题解 | 名字的漂亮度

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void async function () {
    // Write your code here
    const dataNum = await readline()
    while(s = await readline()){
        /**
         * 关键：重复越多的字母，赋予的漂亮度越大，最终s的漂亮度越大
         */
        // 1. 统计字母数量
        let strArr = [...s]
        const letterObj = {}
        strArr.forEach(x => {
            letterObj[x] = letterObj[x] ? letterObj[x] + 1 : 1
        })
        // 2. 根据数量排序
        const arr = Object.keys(letterObj).map(x => [x, letterObj[x]])
        arr.sort((a, b) => b[1] - a[1])
        // 3. 计算结果
        let res = 0
        let startCount = 26
        arr.forEach(x => {
            res += x[1] * startCount
            startCount--
        })
        console.log(res)
    }
}()