题解 | 合并两个排序的链表

/**
 * struct ListNode {
 *  int val;
 *  struct ListNode *next;
 *  ListNode(int x) : val(x), next(nullptr) {}
 * };
 */
class Solution {
  public:
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     *
     *
     * @param pHead1 ListNode类
     * @param pHead2 ListNode类
     * @return ListNode类
     */
    ListNode* Merge(ListNode* pHead1, ListNode* pHead2) {
        // write code here
        ListNode head(0), *cur = &head, *cur1 = pHead1, *cur2 = pHead2;

        while (cur1 && cur2) {
            if (cur1->val < cur2->val) {
                cur->next = cur1;
                cur1 = cur1->next;
            } else {
                cur->next = cur2;
                cur2 = cur2->next;
            }
            cur = cur->next;
        }

        if (cur1) {
            cur->next = cur1;
        } else {
            cur->next = cur2;
        }

        return head.next;
    }
};