题解 | #删除链表的节点#

1. 设置虚拟头结点

ListNode* dummyHead = new ListNode(0);
dummyHead->next = head;

2. 删除节点

        ListNode *cur = dummyHead;
        while (cur->next != NULL) {
            if (cur->next->val == val) {
                ListNode *tmp = cur->next;
                cur->next = cur->next->next;
                delete tmp;
            }
            else {
                cur = cur->next;
            }
        }