题解 | 数位差与数值和的构造

#include <iostream>
#include <string>
using namespace std;

int main() {
    int t;
    cin>>t;
    while(t--){
        string s;
        cin>>s;
        bool turn_A=true;
        string s1="";
        string s2="";
        for(char c:s){
            int digit=(c-'0');
            int half=digit/2;
            if(digit%2==0){
                s1+=(half+'0');
                s2+=(half+'0');
            }else{
                if(turn_A==true){
                    s1+=(half+1+'0');
                    s2+=(half+'0');
                }else{
                    s1+=(half+'0');
                    s2+=(half+1+'0');
                }
                turn_A=!turn_A;
            }
        }
        cout<<stoll(s1)<<" "<<stoll(s2)<<endl;
    }
    return 0;
}
// 64 位输出请用 printf("%lld")