题解 | #杨辉三角的变形#

解题思路：
找规则发现输出以周期为4的循环

i = 0
N = list()
while 1:
    try:
        n = int(input())
        #print('n=',n)        
        def pos(n):
            out = -1
            if n>2:
                if n%4==0:
                    out = 3
                elif n%4==1:
                    out = 2
                elif n%4==2:
                    out = 4
                elif n%4==3:
                    out = 2
            return out        

        print(pos(n))
    except:
        break