题解 | #球的半径和体积#

#include <iostream>
#include <cmath>
using namespace std;

int main() {
    int x0, y0, z0, x1, y1, z1;
    while (cin >> x0 >> y0 >> z0 >> x1 >> y1 >> z1) {
        double r = sqrt(pow(x0 - x1, 2) + pow(y1 - y0, 2) + pow(z0 - z1, 2));
        double pi = acos(-1);
        printf("%.3lf %.3lf", r, 4.0/3*pi*pow(r, 3));
    }
}