题目
- 地上有一个m行和n列的方格。一个机器人从坐标0,0的格子开始移动,每一次只能向左,右,上,下四个方向移动一格,但是不能进入行坐标和列坐标的数位之和大于k的格子。 例如,当k为18时,机器人能够进入方格(35,37),因为3+5+3+7 = 18。但是,它不能进入方格(35,38),因为3+5+3+8 = 19。请问该机器人能够达到多少个格子?
思路
- 本题的主要核心是统计机器人所能达到的格子总数,该函数作用就是统计总数movingCountCore
- 所以需要确定机器人起始点后,开始确认机器人能否到达起点的“前、后、左、右”四个点,这就是用check函数判断某个格子是否为到达点
- 判断函数中有一项重要点:格子坐标位数之和小于规定值,并且是没有去过的点,否则失败
代码
public class Solution {
public int movingCount(int threshold, int rows, int cols){
if(threshold<0 || rows<=0 || cols<=0)
return 0;
Boolean[] flag = new Boolean[rows*cols];
for(int i=0;i<flag.length;i++){
flag[i]=false;
}
int count = movingCountCore(threshold,rows,cols,0,0,flag);
return count;
}
public int movingCountCore(int threshold,int rows,int cols,int row,int col,Boolean[] flag){
int count=0;
if(check(threshold,rows,cols,row,col,flag)==true){
flag[row*rows+col]=true;
count = 1
+movingCountCore(threshold,rows,cols,row-1,col,flag)
+movingCountCore(threshold,rows,cols,row,col-1,flag)
+movingCountCore(threshold,rows,cols,row+1,col,flag)
+movingCountCore(threshold,rows,cols,row,col+1,flag);
}
return count;
}
public boolean check(int threshold,int rows,int cols,int row,int col,Boolean[] flag){
if(row>=0 && col>=0 && col<cols && row<rows &&
(getDigitSum(col)+getDigitSum(row))<=threshold && flag[row*rows+col]==false){
return true;
}
return false;
}
public int getDigitSum(int number){
int sum =0;
while(number>0){
sum+=number%10;
number/=10;
}
return sum;
}
}
链接:https://www.nowcoder.com/questionTerminal/6e5207314b5241fb83f2329e89fdecc8
来源:牛客网
public class Solution {
public int movingCount(int threshold, int rows, int cols)
{
if(threshold < 0 || rows <= 0 || cols <= 0) {
return 0;
}
boolean [] visited = new boolean[rows * cols];
for(int i = 0; i < rows * cols; i ++) {
visited[i] = false;
}
int count = movingCountCore(threshold, rows, cols, 0, 0, visited);
return count;
}
public int movingCountCore(int threshold,int rows,int cols,int row,int col,boolean[] visited) {
int count = 0;
if(check(threshold, rows, cols, row, col, visited)) {
visited[row * cols + col] = true;
count = 1 + movingCountCore(threshold, rows, cols, row - 1, col, visited) //左
+ movingCountCore(threshold, rows, cols, row, col - 1, visited) //上
+ movingCountCore(threshold, rows, cols, row + 1, col, visited) //右
+ movingCountCore(threshold, rows, cols, row, col + 1, visited); //下
}
return count;
}
public boolean check(int threshold, int rows ,int cols, int row, int col, boolean[] visited) {
if(row >= 0 && row < rows && col >= 0 && col < cols && getDigitSum(row) + getDigitSum(col) <= threshold && !visited[row * cols + col]) {
return true;
}
return false;
}
public int getDigitSum(int number) {
int sum = 0;
while(number > 0) {
sum += number % 10;
number /= 10;
}
return sum;
}
}