select u_n,c_n,date from (select u1.name u_n, c1.name c_n, l1.date date, dense_rank() over(partition by u1.name order by l1.date desc) as dk from login l1 join user u1 on l1.user_id = u1.id join client c1 on l1.client_id = c1.id) t1 where t1.dk = 1 order by t1.u_n;
一开始以为要是筛选ios的,多加了选项,后来发现不是筛选ios的,只是做排名,按username排,看题要细心

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