题解 | 求int型正整数在内存中存储时1的个数

import sys

def fun(n):
    count=0
    while n>0:
        if n%2==1:
            count=count+1
            n=n//2
        else:
            n=n//2

    return count


if __name__ == '__main__':
    n= int(input())
    number=fun(n)
    print(number)