题解 | 统计成绩

#include <stdio.h>
int main()
{
    int n;
    float m, k = 0, max = 0, mine = 100;
    scanf("%d", &n);
    for (int i = 0; i < n; i++)
    {
        scanf("%f", &m);
        k += m;
        if (max < m)
        {
            max = m;
        }
        if (mine > m)
        {
            mine = m;
        }
    }
    k /= n;
    printf("%.2f %.2f %.2f", max, mine, k);
    return 0;
}