题解 | 游游的重组偶数

import sys

def solve():
    data = sys.stdin.read().split()
    ptr = 0
    q = int(data[ptr])
    ptr += 1
    for _ in range(q):
        x = str(data[ptr])
        ptr += 1
        output = []
        is_dubble = False
        if int(x) % 2 == 0:
            is_dubble = True
            output.append(x)
            print(''.join(output))
        else:
            x = list(x)
            for i in range(len(x)):
                if int(x[i]) % 2 == 0:
                    x[i],x[len(x)-1] = x[len(x)-1],x[i]
                    is_dubble = True
                    break
            if is_dubble:
                res = ''.join(x)
                output.append(res)
            else:
                output.append('-1')
            print(''.join(output))

solve()