题解 | #数组中只出现一次的两个数字#

from collections import Counter
from typing import List

class Solution:
    def FindNumsAppearOnce(self, nums: List[int]) -> List[int]:
        # 统计每个数字出现的次数
        counte = Counter(nums)
        # 按键（元素本身）排序
        sorted_by_key = sorted(counte.items())
        # 找到只出现一次的数字并返回列表
        return [key for key, count in sorted_by_key if count == 1]