题解 | 小红的不动点构造

#include<bits/stdc++.h>
using namespace std;



int main(){
	int n,k;  cin >> n >> k;
	
	if(k == n-1){
		 cout << -1;
		 return 0;
	}
	
	for(int i=1 ; i <= n ; i++){
		if(i == k+1) continue;
		cout << i << " ";
	}
	
	if(n-k >=2) cout << k+1;
	
	return 0;
}