select uid, (max(datediff(next_time,start_time)) + 1) as days_window, round(count(uid) / (datediff(max(start_time),min(start_time)) + 1) * (max(datediff(next_time,start_time)) +1) ,2) as avg_exam_cnt from (select uid,start_time, lead(start_time) over(partition by uid order by start_time) as next_time from exam_record where year(start_time) = 2021) tb1 group by uid having count( distinct uid,date(start_time)) >=2 order by days_window desc,avg_exam_cnt desc



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