#include <iostream>

using namespace std;

/*
思路：当无法整除2,时，若num%2==1时，则出现1次；进行下一轮计算
*/
int main()
{
    int num;
    int count = 0;
    while(cin>>num) {
        while((num / 2) != 0) {
            if(num % 2 == 1) {
                count++;
            }
            num /= 2;
        }

    }
    cout<<count+1<<endl;
    return 0;
    
}