用c/c++语言编写日历1

用c语言编写日历

#include <stdio.h> 

#include <stdlib.h>

int main()

{
   

	/*定义部分*/

	//定义年月(a,b) 

	int nYear, nMonth, nWeek, d, e, nDays, s;

	printf("请输入年份:");

	scanf_s("%d", &nYear);

	//闰年情况

	if ((nYear % 4 == 0 && nYear % 100 != 0) || (nYear % 400 == 0))

	{
   

		printf("输入的年份为闰年\n");

		d = 0;

	}

	//平年情况

	else

	{
   

		printf("输入的年份为平年\n");

		d = 1;

	}

	printf("请输入月份:");

	scanf_s("%d", &nMonth);

	//闰年

	if (d == 0)

	{
   

		switch (nMonth)

		{
   

		case 1:e = 5, nDays = 31;

			break;

		case 2:e = 1, nDays = 29;

			break;

		case 3:e = 2, nDays = 31;

			break;

		case 4:e = 5, nDays = 30;

			break;

		case 5:e = 0, nDays = 31;

			break;

		case 6:e = 3, nDays = 30;

			break;

		case 7:e = 5, nDays = 31;

			break;

		case 8:e = 1, nDays = 31;

			break;

		case 9:e = 4, nDays = 30;

			break;

		case 10:e = 6, nDays = 31;

			break;

		case 11:e = 2, nDays = 30;

			break;

		case 12:e = 4, nDays = 31;

			break;

		default:

			printf("非法的月份\n"), exit(0);

		}

	}

	//平年

	if (d == 1)

	{
   

		switch (nMonth)

		{
   

		case 1:e = 6, nDays = 31;

			break;

		case 2:e = 2, nDays = 28;

			break;

		case 3:e = 2, nDays = 31;

			break;

		case 4:e = 5, nDays = 30;

			break;

		case 5:e = 0, nDays = 31;

			break;

		case 6:e = 3, nDays = 30;

			break;

		case 7:e = 5, nDays = 31;

			break;

		case 8:e = 1, nDays = 31;

			break;

		case 9:e = 4, nDays = 30;

			break;

		case 10:e = 6, nDays = 31;

			break;

		case 11:e = 2, nDays = 30;

			break;

		case 12:e = 4, nDays = 31;

			break;

		default:

			printf("非法的月份\n"), exit(0);

		}

	}

	int i = nYear - (nYear / 100 * 100);

	s = (((i / 4) + i) % 7 + e + 1) % 7;

	switch (s)

	{
   

	case 0:nWeek = 7;//周日

		break;

	case 1:nWeek = 1;//周一

		break;

	case 2:nWeek = 2;//周二

		break;

	case 3:nWeek = 3;//周三

		break;

	case 4:nWeek = 4;//周四

		break;

	case 5:nWeek = 5;//周五

		break;

	case 6:nWeek = 6;//周六

		break;

	}

	/*打印部分*/

	char ci[7] = " ";//4个空格

	int ni[31];

	int g, k = 1;

	for (g = 0; g < 31; g++)

	{
   

		ni[g] = g + 1;

	}

	printf("\t %4d年%2d月\n一 二 三 四 五 六 日\n", nYear, nMonth);

	for (g = 1; g < nWeek; g++)

	{
   

		printf("%s", ci);

		k++;

	}

	for (g = 0; g < nDays; g++)

	{
   

		printf("%-6d", ni[g]);

		if (k % 7 == 0) printf("\n");

		k++;

	}

	printf("\n");

	system("pause");

	return 0;

}