1.分析
右连接+窗口函数

2.代码

select t2.id,t2.is_group_buy,t1.name as client_name
from client t1 right join
(
    select *,count(id) over(partition by user_id) as number
    from order_info
    where datediff(date,"2025-10-15")>0
    and status="completed"
    and product_name in ("C++","Java","Python")
) t2
on t1.id=t2.client_id
where t2.number >1
order by t2.id