题解 | #求int型正整数在内存中存储时1的个数#

#include <stdio.h>

int main() {
    int a;
    unsigned int result = 0;
    
    scanf("%d", &a);
    for (; a!=0; a=a>>1) {
        if (a%2 == 1) {
            result += 1;
        } else {}
    }
    printf("%d", result);

    return 0;
}