题解 | 牛客的课程订单分析(四)

with flitered_order_info as (
    select
        *,
        count(*) over (partition by user_id) as cnt
    from 
        order_info
    where
        date >= '2025-10-15'
    and 
        product_name in ('C++','Python','Java')
    and 
        status = 'completed'
)

select
    user_id,
    min(date) as first_buy_date,
    min(cnt) as cnt
from 
    flitered_order_info
where 
    cnt >= 2
group by 
    user_id
order by 
    user_id